A survey shows that 63% of the people in a city read news paper A whereas 76% read news paper B. If x% of the people read both the news papers, then a possible value of x can be :

n(A)=63;n(B)=76;n(A∩B)=x% : n(A∩B) is less than the minimum value of n(A),n(B) and more than n(A)+n(B)-n(A∪B)Hence 63+76−100≤nA∩B≤6339≤nA∩B≤63 Therefore, the possible value of n(A∩B) is 55