Symmetric form of the line passing through P ( 2, 2 ) having slope ' 1 ' is
x+2cosπ4=y+2sinπ4
x−2cosπ4=y−2sinπ4
x+2cosπ3=y+2sinπ3
x−2cosπ3=y−2sinπ3
p(2,2) m = tanθ = 1; θ=π4
equation of line in symmetric form
⇒ x−x1cosθ=y−y1sinθ
⇒ x−2cosπ4=y−2sinπ4