The symmetric form of the line passing through a point 1,0,3 and having direction ratios ⟨1,0,3⟩ is
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a
x−1=y=3(z−3)
b
x−11=y0=z+33
c
x−11=y0=z−33
d
x−1=y=-3(z−3)
answer is C.
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Detailed Solution
The equation of a line which is passing through the point (x1,y1,z1) and having direction ratios ⟨a,b,c⟩ is x−x1a=y−y1b=z−z1cTherefore, the equation of a line which is passing through the point 1,0,3 and having direction ratios ⟨1,0,3⟩ is x−11=y0=z-33