Symmetric form of the line through (–2, 0) having slope ‘−13 ’ is
x+2cos5π6+ysin5π6=0
x+2cos5π6=ysin5π6
xcos5π6+y+2sin5π6=0
xcos5π6−y+2sin5π6=0
(x1,y1)=(−2,0)
tanθ=−13
⇒θ=5π6
Eq of line is
x+2cos5π6=y−0sin5π6