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Q.

Symmetric form of the line through (–2, 0) having slope ‘−13 ’ is

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a

x+2cos5π6+ysin5π6=0

b

x+2cos5π6=ysin5π6

c

xcos5π6+y+2sin5π6=0

d

xcos5π6−y+2sin5π6=0

answer is B.

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Detailed Solution

(x1,y1)=(−2,0)                 tanθ=−13                 ⇒θ=5π6                 Eq of line is                x+2cos5π6=y−0sin5π6
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Symmetric form of the line through (–2, 0) having slope ‘−13 ’ is