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The symmetric form of the line whose parametric equations are given by  x=1-2t, y=t, z=-1+t is

a
x−2=y1=z−11
b
x−1−2=y1=z+11
c
x1=y−2=z−1
d
x1=y−2=z1

detailed solution

Correct option is B

The parametric equation of the given line  x=1-2t, y=t, z=-1+t it gives x−1−2=t,y1=t,z+11=tEquation of the given line is x−1−2=y1=z+11

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