The symmetric form of the line whose parametric equations are given by x=1-2t, y=t, z=-1+t is

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x−2=y1=z−11

x−1−2=y1=z+11

x1=y−2=z−1

x1=y−2=z1

answer is B.

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Detailed Solution

The parametric equation of the given line x=1-2t, y=t, z=-1+t it gives x−1−2=t,y1=t,z+11=tEquation of the given line is x−1−2=y1=z+11

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