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The symmetric form of the line $x = a y + b,$ and $z = c y + d$

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x−ab=y1=z−cd

x−ba=y1=z−dc

x+ab=y1=z-cd

x−ba=y1=z+dc

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detailed solution

Correct option is B

The given equation is x=ay+b,and z=cy+dfind the expression for yit implies y=x-ba and y=z-dcTherefore, the equation of the line in symmetric form is x-ba=y1=z-dc

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The symmetric form of the line x=ay+b, and z=cy+d

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The symmetric form of the line $x = a y + b,$ and $z = c y + d$