The symmetric form of the line 2(x+1)=y=z+4
x−(−1)1=y2=z−(−4)2
x−(−1)1=y-2=z−(−4)-2
x−11=y2=z−42
x+10.5=y1=z+42
The symmetric form of any line is in the form of x−x1a=y−y1b=z−z1c
Therefore, the symmetric form of the given line is x−(−1)1=y2=z−(−4)2