The symmetrical form of the equation of the line  x + y + z - 1=0  and 4x+y−2z+2=0 is

D .R of the line ==i¯j¯k¯11141−2=(−3,6,−3) =(1,−2,1) Let Z = K.  Then x = K -1, y = 2 - 2 K.∴(K−1,2−2k,k) is any point on the lineHence (−12,1,12)  (0,0,1)  (−1,2,0) are points on the line,