The system of equations
kx+y+z=k,x+ky+z=k,x+y+kz=k has no solution , If K=
1
2
−2
−1
Since k111k111k=0 ⇒k(k2−1)−1(k−1)+1(1−k)=0
⇒k3−k−k+1+1−k=0
⇒k3−3k+2=0⇒k=1(or)−2
If K=1 Then the equations are coincident
∴k=−2