The system of equations kx+y+z=1,x+ky+z=k and x+y+zk=k2 has no solution if k is
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a
-2
b
-1
c
0
d
1
answer is A.
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Detailed Solution
The augmented matrix of the system of equations is k1111k1k11kk2R2→kR2−R1,R3→kR3−R1 ≈k1110k2−1k−1k2−11k−1k2−1k3−1 ≈k−12k1110k+11k+101k+1k2+k+1R3→k+1R3−R2 ≈k−12k1110k+11k+100k2+2kkk2+2k+1 ≈kk−12k1110k+11k+100k+2k2+2k+1Third equation of the system of equations is k+2z=k+12 z=k+12k+2If k+2=0, system has no solution, it means for k = -2 , system has no solution.