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Q.

The system of equations −2x+y+kz=1,1−2y+3z=2,  x+y−2z=3 is consistent if

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a

a+b+c=0

b

a+b+c≤0

c

k≠−1

d

a+b+c≥0

answer is C.

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Detailed Solution

-21k1-2311-2≠0⇒-2[1]-[-5]+k[3]≠0⇒-2+5+3k≠0⇒3k+3≠0⇒k≠-1
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