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The system of linear equations xy+z=1, x+yz=3, x4y+4z=αhas

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a
A unique solution when α=2
b
A unique solution when α≠2
c
An infinitely number of solutions when α=2
d
An infinitely number of solutions when α=-2

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detailed solution

Correct option is D

givenx−y+z=1______1x+y−z=3______2x−4y+4z=α______3From eqns 1 & 2     x=2⇒y-z=1 & −4y+4z=α−24y−4z+−4y+4z=4+α−2⇒α+2=0⇒α=−2The system of has no solution forα≠−2   If α=−2, then the system is consistent and has infinite number of solutions. (since y-z=1 has infinite number of solutions)


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