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The system of linear equations x+y+z=2, 2x +yz=3, 3x+2y+kz=4  has a unique solution if

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a
k ≠ 0
b
–1
c
– 2
d
k=0

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detailed solution

Correct option is A

The system of equations will have a unique solution if 11121−132k≠0⇒1002−1−33−1k−3≠0                                          [using C1→C1−C1,C3→C3−C1]⇒(k−3)(−1)−3≠0⇒k≠0


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If the system of equations ax + y= 3, x + 2y = 33x + 4y = 7 is consistent, then value of a is given by 


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