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The system of linear equations x+y+z=2,      2x+3y+2z=5       2x+3y+a21z=a+1

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a
has infinitely many solutions for  a=4
b
is inconsistent when a=4
c
has a unique solution for |a|=3
d
is inconsistent when |a|=3

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detailed solution

Correct option is D

According to cramer’s rule , here D=11123223a2−1=10021021a2−3 ( applying C2→C2−C1 and C3→C3−C1=a2−3         ( Expanding along  R1)  And  D1=211532a+13a2−1=21053−1a+13a2−1−3 ( Applving C2→C2−C2=20053−52−1a+13−a+12a2−1−3 ( Applving C2→C2−C2=200512−1a+152−a2a2−4=212a2−4+52−a2 expanding along R1=2a22−2+52−a2=a2−4+5−a=a2−a+1 Clearly, when a=4, then D=13≠0⇒ unique solution and  When |a|=3, then D=0  and D1≠0∴ when |a|=3, then the system has no solution i.e. system is inconsistent.


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