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$T h e c o e f f i c e i n t o f t^{24} i n t h e e x p a n s i o n o f {(1 + t^{2})}^{12} (1 + t^{12}) (1 + t^{24}) i s$

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Correct option is A

The given binomial expansion is (1+t2)121+t121+t24 The coefficient of t24 is C(12,6)+C(12,0)+C(12,12)=C(12,6)+2

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The coefficeint of t24 in the expansion of (1+t2)121+t121+t24 is

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$T h e c o e f f i c e i n t o f t^{24} i n t h e e x p a n s i o n o f {(1 + t^{2})}^{12} (1 + t^{12}) (1 + t^{24}) i s$