The coefficeint of t24 in the expansion of (1+t2)121+t121+t24 is
C12,6+2
C12,6
C12,6+1
C12,7
The given binomial expansion is (1+t2)121+t121+t24 The coefficient of t24 is C(12,6)+C(12,0)+C(12,12)=C(12,6)+2