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Q.

The focus of the parabola is (1,1) and the tangent at the vertex has the equation x+y=1 which of the following is correct

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a

Equation of parabola is x−y2=2x+y−1

b

Equation of parabola is x−y2=4x+y−1

c

The coordinates of the vertex 12,12

d

The length of the latursectum is 22

answer is B.

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Detailed Solution

The distance from focus to the tangent at vertex  is a=2 Directrix is a line parallel to the tangent at vertex and at a distance of 22 units from focusDirectrix is passing through the image of focus in tangent at vertexHence the equation of the directrix is x+y=0By using the definition of the parabola, the locus is x+y22=x−12+y−12x2+y2+2xy=2x2+2y2−4x−4y+4=0x−y2=4x+y−1This is the equation of the parabolaVertex is the foot of the perpendicular of focus on the tangent at vertexhere vertex is 12,12a=12, hence the length of the latusrectum is 22
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