First slide

Equation of line in Straight lines

Question

$T h e l e n g t h o f t h e p e r p e n d i c u l a r f r o m t h e o r i g i n t o a l i n e i s 7 a n d l i n e$ $makes an angle of 150 ° with the$ $p o s i t i v e d i r e c t i o n o f y - a x i s, t h e n t h e e q u a t i o n o f t h e l i n e i s$

Very Easy

A

$\sqrt{3} x + y = 7$
B

$\sqrt{3} x - y = 14$
C

$\sqrt{3} x + y + 14 = 0$
D

$\sqrt{3} x + y - 14 = 0$

Solution

$\begin{array}{l} Here p = 7 and α = 30^{°} \\ ∴ Equation of the required line is \\ x \cos 30^{°} + y \sin 30^{°} = 7 \\ or x \frac{\sqrt{3}}{2} + y \times \frac{1}{2} = 7 \end{array}$
$or \sqrt{3} x + y = 14$

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