$The probability of getting the sum more than 7 when a pair of dice is tossed is$

$\begin{array}{l}\text{Suppose that E be the event of getting sum more than 7 when two dice are thrown}\\ \text{Hence the favorable cases to the event E are }\\ \left(2,6\right),\left(3,5\right),\left(3,6\right),\left(4,4\right),\left(4,5\right),\left(4,6\right),\left(5,3\right),\left(5,4\right),\left(5,5\right),\left(5,6\right),\left(6,2\right),\left(6,3\right),\left(6,4\right),\left(6,5\right),\left(6,6\right)\\ \text{total 15 cases }\\ \text{Hence the probability of E is }\frac{15}{36}=\frac{5}{12}=0.42\end{array}$