First slide

Area of bounded Regions

Question

$T h e a r e a e n c l o s e d b y t h e p a r a b o l a y^{2} = 12 x a n d i t s l a t u s r e c t u m i s$

Very Easy

Solution

$Required area = 2 \int_{0}^{3} ydx$
$= 2 \int_{0}^{3} \sqrt{12} \sqrt{x} dx = 24$

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