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$T a n^{- 1} (\frac{p}{q}) + T a n^{- 1} (\frac{q - p}{q + p}) =$

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detailed solution

Correct option is A

We have, tan-1pq+tan-1q-pq+p=tan-1pq+tan-11-pq1+pq since tan-1x-y1+xy=tan-1x-tan-1y =tan-1pq+tan-11-tan-1pq =π4

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Tan−1pq+Tan−1q−pq+p=

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$T a n^{- 1} (\frac{p}{q}) + T a n^{- 1} (\frac{q - p}{q + p}) =$