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Q.

6tan2⁡x−2cos2⁡x=cos⁡2x if

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a

cos⁡2x=−1

b

cos⁡2x=1

c

cos⁡3x=−1/2

d

cos⁡2x=1/2

answer is D.

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Detailed Solution

6sin2⁡x−2cos4⁡x=cos2⁡x2cos2⁡x−1⇒4cos4⁡x+5cos2⁡x−6=0⇒cos2⁡x=3/4=cos⁡2x=1/2
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