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Questions  

  6tan2⁡x−2cos2⁡x=cos⁡2x if 

a
cos⁡2x=−1
b
cos⁡2x=1
c
cos⁡3x=−1/2
d
cos⁡2x=1/2

detailed solution

Correct option is D

6sin2⁡x−2cos4⁡x=cos2⁡x2cos2⁡x−1⇒4cos4⁡x+5cos2⁡x−6=0⇒cos2⁡x=3/4=cos⁡2x=1/2

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