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Q.

tan2250−cot810cot690cot2610+tan210=

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a

1

b

12

c

3

d

13

answer is C.

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Detailed Solution

tan225=tan(180+45)=tan45=1cot 261=cot(180+81)=cot81tan21=tan(90-69)=cot211−cot810cot690cot810+cot690=−cot(810+690)=−cot1500=3
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