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tan12Sin−12x1+x2−12Cos−11−y21+y2=

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a

2x1−x2

b

0

c

x−y1+xy

d

1

answer is C.

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Detailed Solution

Let x=tanA;y=tanB. Then tan12sin-12x1+x2-12cos-11-x21+x2=tan12sin-12tanA1+tanA2-12cos-11-tanB21+tanB2 =tan12sin-1sin2A-12cos-1cos2B =tanA-B =tanA-tanB1+tanAtanB =x-y1+xy

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