First slide

Compound angles

Question

$\tan A + \tan B + \tan A \tan B - 1 = 0$ then

Easy

A

$A + B = \frac{π}{4}$
B

$A - B = \frac{π}{2}$
C

$A + B = \frac{π}{2}$
D

$A = B = 30^{o}$

Solution

$\begin{array}{l} W e h a v e \tan A + \tan B + \tan A \tan B - 1 = 0 \\ \Rightarrow \frac{\tan A + \tan B}{1 - \tan A \tan B} = 1 \\ \Rightarrow \tan (A + B) = 1 \\ \Rightarrow A + B = \frac{π}{4} \end{array}$

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