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Questions  

tanA+tanB+tanAtanB1=0 then

a
A+B=π4
b
A−B=π2
c
A+B=π2
d
A=B=30o

detailed solution

Correct option is A

We have tanA+tanB+tanAtanB-1=0⇒tanA+tanB1-tanAtanB=1⇒tan(A+B)=1⇒A+B=π4

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