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Questions  

4tan115tan11239 is equal to

a
π
b
π/2
c
π/3
d
π/4

detailed solution

Correct option is D

We have, 4tan−1⁡15−tan−1⁡1239=  2tan−1⁡2/51−1/25−tan−1⁡1239=  2tan−1⁡(5/12)−tan−1⁡1/239=    tan−1⁡2(5/12)1−(5/12)2−tan−1⁡1239=  tan−1⁡120119−tan−1⁡1239=  tan−1⁡120/119−1/2391+120/119×1/239=  tan−1⁡2856928569=tan−1⁡(1)=π4

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