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a
0
b
π2
c
π4
d
tan−1(n−1n+1)
answer is D.
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Detailed Solution
We have tan-111+12+an-111+23+....+an-111+n-1n =tan-12-11+12+an-13-21+23+....+an-1n-n-11++n-1n =tan-12-tan-11+tan-13-tan-12+...+tan-1n-tan-1n-1 =tan-1n-tan-11 =tan-1n-11+n