The tangent of angle between the lines x3+y2=1 and x3−y2=1 is
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a
−512
b
125
c
512
d
∞
answer is B.
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Detailed Solution
The slope of the line xa+yb=1 is m=−ba Hence the slopes of given two lines is m1=−23 and m2=23 If θ be the acute angle between two lines having slopes m1 and m2 then tanθ=m1−m21+m1m2Hence, tanθ=−23−231−49=−4359=125 Therefore, the tangent of angle between the lines is x3+y2=1 and x3−y2=1 is 125