The tangent at any point to the circle x2+y2=16 meets the coordinate axes at A and B. If the lines drawn parallel to axes through A and B meet at ‘P’ Then locus of ‘P’ is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
1x2+1y2=4
b
1x2+1y2=18
c
1x2+1y2=116
d
1x2+1y2=16
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Given circle is x2+y2=16C=(0,0).r=4letP(x1,y1) be the point on locus⇒A(x1,0) B(0,y1)∴eq. of AB→ is xx1+yy1=1 …………….(1)Since equation (1) touches the circler=d⇒4=11x12+1y12 ⇒1x12+1y12=14S.O.B.S⇒1x12+1y12=116∴ locus is 1x2+1y2=116