A tangent at any point to the ellipse 4x2+9y2=36 is cut by the tangent at the extremities of the major axis at T′ T and '. The circle on TT′ as diameter passes through the point.
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a
(0,5)
b
(5,0)
c
(2,1)
d
(0,−5)
answer is B.
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Detailed Solution
Any point on the ellipse is P(3cosθ,2sinθ)Equation of the tangent at P is x3cosθ+y2sinθ=1 which meets the tangents x=3 and x=−3 at the extremities of the major axis at T3,2(1−cosθ)sinθ and T′−3,2(1+cosθ)sinθ Equation of the circle on TT′ as diameter is (x−3)(x+3)+y−2(1−cosθ)sinθy−2(1+cosθ)sinθ=0⇒x2+y2−4sinθy−5=0 which passes through (5,0)
A tangent at any point to the ellipse 4x2+9y2=36 is cut by the tangent at the extremities of the major axis at T′ T and '. The circle on TT′ as diameter passes through the point.