The tangent and normal at the point A(4,4) to the parabola y2=4x intersect x -axis at the points B and C respectively, then the equation of circumcircle of △ABC is

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x2+y2−4x−6y=0

x2+y2−4x+6y=0

x2+y2+4x−6y=0

x2+y2−2x−24=0

answer is D.

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Detailed Solution

B=(−4,0),C=(6,0) are ends of diameter of circle. eq. of circle is (x+4)(x−6)+y2=0

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