The tangent and normal at the point A(4,4) to the parabola y2=4x intersect x -axis at the
points B and C respectively, then the equation of circumcircle of △ABC is
x2+y2−4x−6y=0
x2+y2−4x+6y=0
x2+y2+4x−6y=0
x2+y2−2x−24=0
B=(−4,0),C=(6,0) are ends of diameter of circle.
eq. of circle is (x+4)(x−6)+y2=0