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Questions  

 The tangent and normal at the point A(4,4) to the parabola y2=4x intersect x -axis at the 

 points B and C respectively, then the equation of circumcircle of ABC is 

a
x2+y2−4x−6y=0
b
x2+y2−4x+6y=0
c
x2+y2+4x−6y=0
d
x2+y2−2x−24=0

detailed solution

Correct option is D

B=(−4,0),C=(6,0) are ends of diameter of circle.  eq. of circle is (x+4)(x−6)+y2=0

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