First slide
Parabola
Question

The tangent at a point P on the parabola y2 = 8x 

meets the directrix of the parabola at Q such that  

distance of Q from the axis of the parabola is 3. 

Then the coordinates of P cannot be

Moderate
Solution

Equation of the tangent at  P (2t2 , 4t) to the parabola is ty = x + 2t 2 which meets the directrix x =2 of the parabola at Q for which y=2t22t. So that 2t22t=±3

.2t23t2=0 or  2t2+3t2=0

(2t+1)(t2)=0 or  (2t1)(t+2)=0

t=±2,±12

So, the coordinates of P are (8,±8) or  12,±2

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