Download the app

Questions  

The tangent at a point P on the parabola y2 = 8x 

meets the directrix of the parabola at Q such that  

distance of Q from the axis of the parabola is 3. 

Then the coordinates of P cannot be

a
(2, 4)
b
(8, 8)
c
(1/2, 2)
d
(8 – 8)

detailed solution

Correct option is A

Equation of the tangent at  P (2t2 , 4t) to the parabola is ty = x + 2t 2 which meets the directrix x =–2 of the parabola at Q for which y=2t2−2t. So that 2t2−2t=±3.⇒2t2−3t−2=0 or  2t2+3t−2=0⇒(2t+1)(t−2)=0 or  (2t−1)(t+2)=0⇒t=±2,±12So, the coordinates of P are (8,±8) or  12,±2

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

The points of intersection of curves whose parametric equations are x=t2+1,y=2t  and x=2S,y=2S is


phone icon
whats app icon