Tangents are drawn from a point on the circle x2+y2−4x+6y−37=0 to the circle x2+y2−4x+6y−12=0The angle between the tangents, is
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a
π4
b
π3
c
π6
d
π2
answer is D.
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Detailed Solution
the equations of the circles are: (x−2)2+(y+3)2=(52)2 .......(i)and (x−2)2+(y+3)2=52 (ii)Clearly, (i) is the direction circle of (ii). So, required angle is π2