The tangents are drawn from the points of a straight line 3x+4y=24 to the curve x2+y24=1. Then all the chords of contact passes through a fixed point (a,b), then 2a+3b

Let the coordinates of a point lying on the straight line 3x+4y=24 is t,24−3t4 Equation of the chord of contact is tx+y16(24−3t)=1⇒(24y−16)+t(16x−3y)=0⇒ this line always passes through the fixed point which is the point of intersection of the  lines 24y−16=0 and 16x−3y=0 fixed point ≡18,23, which lies on 16x−3y=0,9y2=32x and 24x+24y=19.⇒a=18,b=23 ∴2a+3b=14+2=2.25