The tangents drawn from the origin to the circle
x2+y2−2rx−2hy+h2=0 are perpendicular, if
h=±r
h=±2r
h2+r2=1
h=±3r
The combined equation of the tangents drawn from (0,0) to x2+y2−2rx−2hy+h2=0, is
x2+y2−2rx−2hy+h2h2=−rx−hy+h22
This equation represents a pair of perpendicular straight lines if
Coeff. of x2+ Coeff. of y2=0
⇒ 2h2−r2−h2=0⇒r2=h2⇒r=±h