A team of four students is to be selected from a total of 12 students. The total number of ways in which the. team can be selected such that two particular students refuse to be together and other two particular students wish to be together only is equal to

Let S1 and S2 refuse to be together and S3 and S4 want to be together only. The total number of ways when S3 and S4 are selected is 8C2+2C1×8C1=44. The total ways when S3 and S4 are not selected is  8C4+2C1×8C3=182. Thus, the total number of ways is 44 + 182 = 226.