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The tensdigit of 1! + 2! + 3! + … + 49! is
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Correct option is A
We know that 1! + 2! + 3! + 4! = 33Also, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.Thus, tens digit of 1! + 2! + … + 9! is 1.Also, note that n! is divisible by 100 for all n ≥ 10. Therefore, the tens digit of 1! + 2! + … + 49! is 1.Similar Questions
Let (where, [ . ] denotes greatest integer function) is equal to
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