The term contacting x3 in the expansion of (x−2y)7 is
3rd
4th
5th
6th
Given expansion is (x−2y)7
We have general term in the expansion (x+a)n
(∴ Tr+1= nCr xn−r (a)r be the expansion of (x+a)n)
Tr+1= 7Crx7−r(−2y)r
x7−r compare with x3 then
⇒x7−r=x3
Contains x3 it 7−r=3
∵r=4 .
So T5 is the required term.