Questions
The term independent of x in the expansion of is equal to
a
-72
b
36
c
-36
d
-108
detailed solution
Correct option is C
Let a binomial 2x2−3x26, it's (r+1) th term =Tr+1=6Cr2x26−r−3x2r=6Cr(−3)r(2)6−rx12−2r−2r ---(i)=6Cr(−3)r(2)6−rx12−4r Now, the term independent of x in the expansion of 160−x8812x2−3x26= the term independent of x in the expansion of 1602x2−3x26 the term independent of x in the expansion of −x8812x2−3x26= 6C360(−3)3(2)6−3x12−4(3)+−1816C5(−3)5(2)6−5x12−4(5)x8=13(−3)323+35×2(6)81=36−72=−36Talk to our academic expert!
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lf the term independent of x in the expansion of is k, then 18k is equal to
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