First slide

Binomial theorem for positive integral Index

Question

$The term independent of x in the expansion of {(x^{2} - \frac{1}{x})}^{6} is$

Moderate

A

-12
B

15
C

24
D

-15

Solution

$\begin{array}{l} r = \frac{6 \times 2}{2 + 1} = \frac{12}{3} = 4 . \\ ∴ Ther terms independent of x {is}^{6} C_{4} {(x^{2})}^{2} {(- \frac{1}{x})}^{4} \\ =^{6} C_{2} = 15 \end{array}$

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