The term independent of x in (1+x)m1+1xn

We have, (1+x)m1+1xn=(1+x)mx+1xn=(1+x)m+nxn=x−n(1+x)m+n∴Required term independent of x = coefficient of x0 inx−n(1+x)m+n =coefficient of xn in (1+x)m+n                          =m+nCn