The term void of x in the expansion of (x3+3x2)10 is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
59
b
259
c
53
d
None of these
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Given expansion is (x3+3x2)10 then we have to find independent term General term in the expansion Tr+1= nCr xn−r ar Tr+1= 10Cr(x3)10−r(3x2)r (simplication of x terms and constant) = 10Crx10−r2−2r 3r−5 ( these x term compare with x0 )This term is independent of x if x10−r2−2r=x0 powers are equal then we get i.e. if r=2 henceT2+1= 10C2 (x3)10−2 (3x2)2⇒T3= 10C2 (x3)8 (3x2)2 = 10C2 3−3 =10×92×127=53 (∴ nCr=n!(n−r)!r!)