First slide

Introduction to 3-D Geometry

Question

In the tetrahedron ABCD, A=(2, 3, 7), G=(–1, 2, 4) is centroid of tetrahedron if P is the centroid of triangle BCD then AP =

Difficult

A

$\frac{4}{3} \sqrt{19}$
B

$\frac{8}{3} \sqrt{19}$
C

$4 \sqrt{19}$
D

$\frac{\sqrt{19}}{3}$

Solution

$A P = \frac{4}{3} A G$
= $\frac{4}{3} \sqrt{9 + 1 + 9}$

= $\frac{4}{3} \sqrt{19}$

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