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 The 10th  common term between the series 3+7+11+.. and 1+6+11+. is 

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a
191
b
193
c
211
d
None of these

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detailed solution

Correct option is A

First common term a =11LCM of two common difference = L.C.M of 4 and 5Common difference , d = 20Tn=a+(n−1)dT10=11+9d=11+9(20)=11+180=191


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The sum of n terms of an A.P. is 3n2+5 The number of  term which equals 159, is


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