First slide

Binomial theorem for positive integral Index

Question

$The 4^{th} term in the expansion of {(\sqrt{x} + \frac{1}{x})}^{12} is$

Very Easy

A

$110 x^{\frac{3}{2}}$
B

$220 x^{\frac{3}{2}}$
C

$110 x^{2}$
D

$220 x^{2}$

Solution

$4^{t h} t e r m i n t h e e x p a n s i o n o f {(\sqrt{x} + \frac{1}{x})}^{12} i s T_{4} = {}^{12}C_{3} {(\sqrt{x})}^{12 - 3} {(\frac{1}{x})}^{3} = 220 x^{\frac{3}{2}}$

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