First slide

Binomial theorem for positive integral Index

Question

$5^{th} term of {(2 x^{2} + \frac{3}{x})}^{5} is 10 . Then x =$

Moderate

A

$\pm 3$
B

3
C

$\pm 9$
D

9

Solution

$5^{th} term = 10 \Rightarrow^{5} C_{4} {(2 x^{2})}^{54} {(\frac{3}{x})}^{^{4}} = 10 \Rightarrow \frac{81}{x^{2}} = 1 \Rightarrow x = \pm 9$

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