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There are four numbers of which the first three are in  G.P. whose common ratio is 12 and the last three are   in A.P. If the last number is two less than the first, then  the four members are

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a
3,1,13,−13
b
2,1,12,0
c
4,1,14,−12
d
None of these

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detailed solution

Correct option is B

The numbers can be taken as a,a2,a4,a−2.By question, a2,a4,a−2 are in AP.∴ 2⋅a4=a2+a−2; or a=2. Hence, the numbers are 2,1,12,0.


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