First slide

Theorems of probability

Question

There are 4 green, 6 black and 7 white balls in a bag. A ball is drawn at random from the bag. The probability that it may be either green or black is

Easy

A

$\frac{5}{17}$
B

$\frac{1}{3}$
C

$\frac{10}{17}$
D

$\frac{7}{17}$

Solution

$P (A) = \frac{4_{c_{_{1}}} + 6_{c_{_{1}}}}{17_{c_{_{1}}}} = \frac{10}{17}$

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