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Q.

There are n concurrent lines and another line parallel to one of them. The number of different triangles that will be formed by the (n + 1) lines, is

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a

(n−1)n2

b

(n−1)(n−2)2

c

n(n+1)2

d

(n+1)(n+2)2

answer is B.

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Detailed Solution

The number of triangles = number of selections of 2 lines from the (n – 1) lines which are cut by the last line=n−1C2=(n−1)!2!(n−3)!=(n−1)(n−2)2
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