There are(n+1) white similar balls and (n+1) black balls of different size. No. of ways the balls can be arranged in a row so that adjacent balls are of different colours is
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a
[(n+1) !]2
b
2[(2n)!]
c
2[(n+1)!]
d
2[(n+1)!]2
answer is C.
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Detailed Solution
=2(n+1)!×(n+1)!(n+1)!(∵white balls are similar) =2(n+1)! No. of ways the balls can be arranged in a row so that adjacent balls are of different colours is 2[(n+1)!]
There are(n+1) white similar balls and (n+1) black balls of different size. No. of ways the balls can be arranged in a row so that adjacent balls are of different colours is