First slide

Combinations

Question

There are 10 points in a plane of which no three points are collinear and 4 points are concyclic. The number of different circles that can be drawn through at least 3 of these points is

Moderate

A

116
B

120
C

117
D

None of these

Solution

The required number of circles $= (^{10} C_{3} -^{4} C_{3}) + 1 = 117$ .

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App